The subset of numbers are arranged in a sort of binary code format. Those numbers actually see themselves placed inside of the subnet which is listed as 128 and 191. This would explain the answer as being option A because the subnet and the broadcast numbers are listed as 129 and 190 which again is inside of the subset of numbers. Internet protocol addresses are something that is part of the online world that is complex but it is vital to making sure that the internet is able to function and move the way that it does.
This IP address is very familiar to a lot of people because it is used for people to be able to log into their own computer and customize the IP address. It goes to show the complexity and wide utilization of the 192.168 address. In the end though the answer here would be the 192.168.168.129-190 because these numbers fall inside of the subset of numbers that are being given in the example.
256 - 192 = 64. 64 + 64 = 128. 128 + 64 = 192. The subnet is 128, the broadcast address is 191, and the valid host range is the numbers in between, or 129-190.