What is the output of the following?

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echo strncasecmp(hello world, HelloWorld, 5), , ;
echo strcmp(44, 054), , ;
echo strcasecmp(xyz, ABC), , ;
echo strncmp(0, Z, 1), , ;
echo strcmp(bb, aaaa);

Asked by Aquiline, Last updated: Nov 09, 2024

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1 Answer

John Smith

Answered Sep 08, 2016

0, 0, -23, -1, 1-e) is correct because for the first one, strncasecmp compares str1 to str2 in a case-insensitive fashion, for the first 5 charactersfor the second one, 054 (octal 44) is converted to decimal first, and then 44 == 44for the third one, strcasecmp, xyz is converted to uppercase or abc is converted to lowercase, and a is 23 positions away from x in asciifor the fourth one, 0 is compared to z, for the first 1 characters, letters (even uppercase ones) take precedence over numbersfinally, for the fourth one. even though bb is shorter than aaaa, b is higher than a, so str1 is greater