Correct answer is option A
First, we need to find the resistance
R = V^2/P
R = 230 *230/10000
R = 52,900/10000
R = 5.29 ohms
Now, since we know the resistance and the voltage connected we can find the power
P = V^2/R
P = 208*208/5.29
P = 43,264/5.29
P = 8,178.45 watts
Approximate power = 8000 watts (8kW)
The power of the heat strip will be less because the Applied voltage (208V) is less than equipment voltage Rating (230V). To calculate this, we must determine the Heat strip resistance rating at 230V, and then determine The power rating at 208V base on the heat strip resist- Ance rating. P= E/R E = Applied Voltage = 208V R = Resistance of Heat Strip = E/P Heat Strip Voltage Rating = 230V Power Rating of Heat Strip = 10,000W Resistance of Heat Strip= 230V/10,000W Resistance of Heat Strip= 5.29 ohms P = E/R P = (208V x 208V)/5.29 ohms P = 43,624/5.29 ohms P = 8,178W/1,000 = 8.2 kW