What is the molarity of the acid in the following scenario?

Question

what is the molarity of the acid in the following scenario? a 15.5 ml sample of 0.215 m koh was titrated with a weak acid. IT took 21.2 ml of the acid to reach the equivalence point.

John Adney · Accepted Answer

Volume of acid  M of acid = V of base  M of BaseM of acid = V of base  M of Base/volume of acidM of acid = 0.0155L0.215M/0.212 LM of acid = 0.0157M

What is the molarity of the acid in the following scenario?

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