How much time will it take for the ball to reach the ground and at what height will the ball be after each second of motion?
Anna Litical drops a ball from rest from the top of 78.4-meter high cliff.
It will take 4 seconds to fall 78.4 meters
Use the equation y = 0.5 g t2 and substitute -9.8 m/s/s for g. The vertical displacement must then be subtracted from the initial height of 78. 4 m.
At t = 1 s, y = 4.9 m (down) so height is 73.5 m (78.4 m - 4.9 m )
At t = 2 s, y = 19.6 m (down) so height is 58.8 m (78.4 m - 19.6 m )
At t = 3 s, y = 44.1 m (down) so height is 34.3 m (78.4 m - 45 m)
At t = 4 s, y = 78.4 m (down) so height is 0 m (78.4 m - 78.4 m)
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