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What is the empirical formula for a compound that is 43.6% phosphorus and 56.4% oxygen?

What is the empirical formula for a compound that is 43.6% phosphorus and 56.4% oxygen?

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Asked by Mmccoy, Last updated: Nov 11, 2024

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L. Brett

L. Brett

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L. Brett
L. Brett, Sales Manager, MBA, Detroit

Answered Mar 28, 2019

The empirical formula for a compound that is 43.6% phosphorus and 56.4% oxygen is P2O5. In the formula, the P stands for phosphorus and the O standards for oxygen, so there are 2 phosphorus (P) atoms and 5 oxygen (O) atoms in the compound.

The atomic mass of phosphorus (P) is 30.974 u and the atomic mass of oxygen (O) is 15.999 u. Therefore, the total weight of phosphorus in the compound is 61.948, and the total weight of oxygen in the compound is 79.995. The total weight of the compound is 141.943, so phosphorus is 43.6% of the compound and oxygen is 56.4%.

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mmccoy14

mmccoy

mmccoy14
Mmccoy

Answered Mar 08, 2018

P2o5
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